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The tangents to a circle are equal in length

If P is a point in the exterior of the circle C, then if M and N are on C so that PM and PN are tangent with C we have:
$ PM = PN $
Indeed,$ \triangle POM=\triangle PON $
as both are right triangles,OP is common and OM=ON=radius
Then all others correspondent elements are congruent.PM=PN
Also we have PO is the bisector of angle MPN

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